1/3(2m-3)=1/4(m-4)

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Solution for 1/3(2m-3)=1/4(m-4) equation: 



1/3(2m-3)=1/4(m-4)

We move all terms to the left:

1/3(2m-3)-(1/4(m-4))=0



Domain of the equation: 3(2m-3)!=0

m∈R





Domain of the equation: 4(m-4))!=0

m∈R



We calculate fractions


(4mm/(3(2m-3)*4(m-4)))+(-3m2/(3(2m-3)*4(m-4)))=0



We calculate terms in parentheses: +(4mm/(3(2m-3)*4(m-4))), so:

4mm/(3(2m-3)*4(m-4))

We multiply all the terms by the denominator


4mm

Back to the equation:

+(4mm)





We calculate terms in parentheses: +(-3m2/(3(2m-3)*4(m-4))), so:

-3m2/(3(2m-3)*4(m-4))

We multiply all the terms by the denominator


-3m2

We add all the numbers together, and all the variables

-3m^2

Back to the equation:

+(-3m^2)



We get rid of parentheses

-3m^2+4mm=0

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