1/3(2b+9)=2/3(1b+9/2)

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Solution for 1/3(2b+9)=2/3(1b+9/2) equation: 


b in (-oo:+oo)

(1/3)*(2*b+9) = (2/3)*(1*b+9/2) // - (2/3)*(1*b+9/2)

(1/3)*(2*b+9)-((2/3)*(1*b+9/2)) = 0

(1/3)*(2*b+9)+(-2/3)*(b+9/2) = 0

1/3*(2*b+9)-2/3*(b+9/2) = 0

1/3*(2*b+9)-2/3*(b+9/2) = 0

0 = 0

0 = 0

b belongs to the empty set

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