1/3(24x+36)-3x=18x-5(3x+6)

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Solution for 1/3(24x+36)-3x=18x-5(3x+6) equation: 



1/3(24x+36)-3x=18x-5(3x+6)

We move all terms to the left:

1/3(24x+36)-3x-(18x-5(3x+6))=0



Domain of the equation: 3(24x+36)!=0

x∈R



We add all the numbers together, and all the variables

-3x+1/3(24x+36)-(18x-5(3x+6))=0

We multiply all the terms by the denominator


-3x*3(24x+36)-((18x-5(3x+6)))*3(24x+36)+1=0



We calculate terms in parentheses: -((18x-5(3x+6)))*3(24x+36), so:

(18x-5(3x+6)))*3(24x+36



Wy multiply elements

-9x^2(2-((18x-5(3x+6)))*3(24x+36)+1=0

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