1/3(18x-12)=8x-6

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Solution for 1/3(18x-12)=8x-6 equation: 



1/3(18x-12)=8x-6

We move all terms to the left:

1/3(18x-12)-(8x-6)=0



Domain of the equation: 3(18x-12)!=0

x∈R



We get rid of parentheses

1/3(18x-12)-8x+6=0

We multiply all the terms by the denominator


-8x*3(18x-12)+6*3(18x-12)+1=0

Wy multiply elements

-24x^2(1+18x(1+1=0

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