1/3(18x+15)=1/7(35x-56)

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Solution for 1/3(18x+15)=1/7(35x-56) equation:



1/3(18x+15)=1/7(35x-56)
We move all terms to the left:
1/3(18x+15)-(1/7(35x-56))=0
Domain of the equation: 3(18x+15)!=0
x∈R
Domain of the equation: 7(35x-56))!=0
x∈R
We calculate fractions
(7x3/(3(18x+15)*7(35x-56)))+(-3x1/(3(18x+15)*7(35x-56)))=0
We calculate terms in parentheses: +(7x3/(3(18x+15)*7(35x-56))), so:
7x3/(3(18x+15)*7(35x-56))
We multiply all the terms by the denominator
7x3
We add all the numbers together, and all the variables
7x^3
We do not support expression: x^3

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