1/3(18m-6)=1/5(10m+30)

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Solution for 1/3(18m-6)=1/5(10m+30) equation: 



1/3(18m-6)=1/5(10m+30)

We move all terms to the left:

1/3(18m-6)-(1/5(10m+30))=0



Domain of the equation: 3(18m-6)!=0

m∈R





Domain of the equation: 5(10m+30))!=0

m∈R



We calculate fractions


(5m1/(3(18m-6)*5(10m+30)))+(-3m1/(3(18m-6)*5(10m+30)))=0



We calculate terms in parentheses: +(5m1/(3(18m-6)*5(10m+30))), so:

5m1/(3(18m-6)*5(10m+30))

We multiply all the terms by the denominator


5m1

We add all the numbers together, and all the variables

5m

Back to the equation:

+(5m)





We calculate terms in parentheses: +(-3m1/(3(18m-6)*5(10m+30))), so:

-3m1/(3(18m-6)*5(10m+30))

We multiply all the terms by the denominator


-3m1

We add all the numbers together, and all the variables

-3m

Back to the equation:

+(-3m)



We get rid of parentheses

5m-3m=0

We add all the numbers together, and all the variables

2m=0

m=0/2

m=0

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