1/3(18+6x)=2/5(10x+30)

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Solution for 1/3(18+6x)=2/5(10x+30) equation: 



1/3(18+6x)=2/5(10x+30)

We move all terms to the left:

1/3(18+6x)-(2/5(10x+30))=0



Domain of the equation: 3(18+6x)!=0

x∈R





Domain of the equation: 5(10x+30))!=0

x∈R



We add all the numbers together, and all the variables

1/3(6x+18)-(2/5(10x+30))=0

We calculate fractions


(5x1/(3(6x+18)*5(10x+30)))+(-6x6/(3(6x+18)*5(10x+30)))=0



We calculate terms in parentheses: +(5x1/(3(6x+18)*5(10x+30))), so:

5x1/(3(6x+18)*5(10x+30))

We multiply all the terms by the denominator


5x1

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-6x6/(3(6x+18)*5(10x+30))), so:

-6x6/(3(6x+18)*5(10x+30))

We multiply all the terms by the denominator


-6x6

We add all the numbers together, and all the variables

-6x^6

We do not support expression: x^6

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