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1/3(12x-9)=6x+3-2x
We move all terms to the left:
1/3(12x-9)-(6x+3-2x)=0
Domain of the equation: 3(12x-9)!=0We add all the numbers together, and all the variables
x∈R
1/3(12x-9)-(4x+3)=0
We get rid of parentheses
1/3(12x-9)-4x-3=0
We multiply all the terms by the denominator
-4x*3(12x-9)-3*3(12x-9)+1=0
Wy multiply elements
-12x^2(1-9x(1+1=0
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