1/3(12x-18)=7x+33+3x

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Solution for 1/3(12x-18)=7x+33+3x equation: 



1/3(12x-18)=7x+33+3x

We move all terms to the left:

1/3(12x-18)-(7x+33+3x)=0



Domain of the equation: 3(12x-18)!=0

x∈R



We add all the numbers together, and all the variables

1/3(12x-18)-(10x+33)=0

We get rid of parentheses

1/3(12x-18)-10x-33=0

We multiply all the terms by the denominator


-10x*3(12x-18)-33*3(12x-18)+1=0

Wy multiply elements

-30x^2(1-99x(1+1=0

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