1/3(12x-18)=1/2x+36

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Solution for 1/3(12x-18)=1/2x+36 equation: 



1/3(12x-18)=1/2x+36

We move all terms to the left:

1/3(12x-18)-(1/2x+36)=0



Domain of the equation: 3(12x-18)!=0

x∈R





Domain of the equation: 2x+36)!=0

x∈R



We get rid of parentheses

1/3(12x-18)-1/2x-36=0

We calculate fractions


2x/(72x^2-108x)+(-3x1/(72x^2-108x)-36=0

We calculate fractions

We do not support expression: x^3

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