1/3(12x-15)=1/2(10x+22)

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Solution for 1/3(12x-15)=1/2(10x+22) equation: 



1/3(12x-15)=1/2(10x+22)

We move all terms to the left:

1/3(12x-15)-(1/2(10x+22))=0



Domain of the equation: 3(12x-15)!=0

x∈R





Domain of the equation: 2(10x+22))!=0

x∈R



We calculate fractions


(2x1/(3(12x-15)*2(10x+22)))+(-3x1/(3(12x-15)*2(10x+22)))=0



We calculate terms in parentheses: +(2x1/(3(12x-15)*2(10x+22))), so:

2x1/(3(12x-15)*2(10x+22))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-3x1/(3(12x-15)*2(10x+22))), so:

-3x1/(3(12x-15)*2(10x+22))

We multiply all the terms by the denominator


-3x1

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

2x-3x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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