1/3(12x+27)-5=3/5(40x-25)

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Solution for 1/3(12x+27)-5=3/5(40x-25) equation: 



1/3(12x+27)-5=3/5(40x-25)

We move all terms to the left:

1/3(12x+27)-5-(3/5(40x-25))=0



Domain of the equation: 3(12x+27)!=0

x∈R





Domain of the equation: 5(40x-25))!=0

x∈R



We calculate fractions


(5x4/(3(12x+27)*5(40x-25)))+(-9x1/(3(12x+27)*5(40x-25)))-5=0



We calculate terms in parentheses: +(5x4/(3(12x+27)*5(40x-25))), so:

5x4/(3(12x+27)*5(40x-25))

We multiply all the terms by the denominator


5x4

We add all the numbers together, and all the variables

5x^4

We do not support expression: x^4

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