1/3(12-4a)=1/3(3-9a)

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Solution for 1/3(12-4a)=1/3(3-9a) equation: 



1/3(12-4a)=1/3(3-9a)

We move all terms to the left:

1/3(12-4a)-(1/3(3-9a))=0



Domain of the equation: 3(12-4a)!=0

a∈R





Domain of the equation: 3(3-9a))!=0

a∈R



We add all the numbers together, and all the variables

1/3(-4a+12)-(1/3(-9a+3))=0

We calculate fractions


(3a(-)/(3(-4a+12)*3(-9a+3)))+(-3a0/(3(-4a+12)*3(-9a+3)))=0



We calculate terms in parentheses: +(3a(-)/(3(-4a+12)*3(-9a+3))), so:

3a(-)/(3(-4a+12)*3(-9a+3))

We add all the numbers together, and all the variables

3a0/(3(-4a+12)*3(-9a+3))

We multiply all the terms by the denominator


3a0

We add all the numbers together, and all the variables

3a

Back to the equation:

+(3a)





We calculate terms in parentheses: +(-3a0/(3(-4a+12)*3(-9a+3))), so:

-3a0/(3(-4a+12)*3(-9a+3))

We multiply all the terms by the denominator


-3a0

We add all the numbers together, and all the variables

-3a

Back to the equation:

+(-3a)



We get rid of parentheses

3a-3a=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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