1/3(12-27x)=3/4(16x-24)

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Solution for 1/3(12-27x)=3/4(16x-24) equation: 



1/3(12-27x)=3/4(16x-24)

We move all terms to the left:

1/3(12-27x)-(3/4(16x-24))=0



Domain of the equation: 3(12-27x)!=0

x∈R





Domain of the equation: 4(16x-24))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-27x+12)-(3/4(16x-24))=0

We calculate fractions


(4x1/(3(-27x+12)*4(16x-24)))+(-9x0/(3(-27x+12)*4(16x-24)))=0



We calculate terms in parentheses: +(4x1/(3(-27x+12)*4(16x-24))), so:

4x1/(3(-27x+12)*4(16x-24))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-9x0/(3(-27x+12)*4(16x-24))), so:

-9x0/(3(-27x+12)*4(16x-24))

We multiply all the terms by the denominator


-9x0

We add all the numbers together, and all the variables

-9x

Back to the equation:

+(-9x)



We get rid of parentheses

4x-9x=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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