1/3(12-24c)=-2(4c-2)

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Solution for 1/3(12-24c)=-2(4c-2) equation: 



1/3(12-24c)=-2(4c-2)

We move all terms to the left:

1/3(12-24c)-(-2(4c-2))=0



Domain of the equation: 3(12-24c)!=0

c∈R



We add all the numbers together, and all the variables

1/3(-24c+12)-(-2(4c-2))=0

We multiply all the terms by the denominator


-((-2(4c-2)))*3(-24c+12)+1=0



We calculate terms in parentheses: -((-2(4c-2)))*3(-24c+12), so:

(-2(4c-2)))*3(-24c+12

We add all the numbers together, and all the variables

-24c+(-2(4c-2)))*3(+12

Back to the equation:

-(-24c+(-2(4c-2)))*3(+12)



We add all the numbers together, and all the variables

-(-24c+(-2(4c-2)))*312+1=0

We move all terms containing c to the left, all other terms to the right

-(-24c+(-2(4c-2)))*312=-1

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