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1/3(12+x)=-8(6-8)
We move all terms to the left:
1/3(12+x)-(-8(6-8))=0
Domain of the equation: 3(12+x)!=0We add all the numbers together, and all the variables
x∈R
1/3(x+12)-(-8(-2))=0
We add all the numbers together, and all the variables
1/3(x+12)-16=0
We multiply all the terms by the denominator
-16*3(x+12)+1=0
Wy multiply elements
-48x(x+1=0
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