1/3(10y-2)+1/9(6y+10)

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Solution for 1/3(10y-2)+1/9(6y+10) equation:


y in (-oo:+oo)

(1/3)*(10*y-2)+(1/9)*(6*y+10) = 0

1/3*(10*y-2)+1/9*(6*y+10) = 0

1/3*(10*y-2)+1/9*(6*y+10) = 0

4*y+4/9 = 0

4*y+4/9 = 0

4*y+4/9 = 0 // - 4/9

4*y = -4/9 // : 4

y = -4/9/4

y = -1/9

y = -1/9

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