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1/3(-3)+y=12
We move all terms to the left:
1/3(-3)+y-(12)=0
determiningTheFunctionDomain y-12+1/3(-3)=0
We multiply all the terms by the denominator
y*3(-3)+1-12*3(-3)=0
We add all the numbers together, and all the variables
y*3(-3)+109=0
Wy multiply elements
3y^2(-+109=0
We use the square of the difference formula
3y^2(-109=0
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