1/2z+6=3/2(z=6)

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Solution for 1/2z+6=3/2(z=6) equation: 



1/2z+6=3/2(z=6)

We move all terms to the left:

1/2z+6-(3/2(z)=0



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R





Domain of the equation: 2z+6!=0

We move all terms containing z to the left, all other terms to the right

2z!=-6

z!=-6/2

z!=-3

z∈R



We calculate fractions


(2z+6)/(4z^2+6)+(-(3*2z)/(4z^2+6)=0



We calculate terms in parentheses: +(-(3*2z)/(4z^2+6), so:

-(3*2z)/(4z^2+6

We add all the numbers together, and all the variables

-(+3*2z)/(4z^2+6

We multiply all the terms by the denominator


-(+3*2z)

We get rid of parentheses

-3*2z

Wy multiply elements

-6z

Back to the equation:

+(-6z)



We get rid of parentheses

(2z+6)/(4z^2+6)-6z=0

We multiply all the terms by the denominator


(2z+6)-6z*(4z^2+6)=0

We multiply parentheses

-24z^3+(2z+6)-36z=0

We get rid of parentheses

-24z^3+2z-36z+6=0

We do not support ezpression: z^3

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