If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2z+10+3/4=1/4z
We move all terms to the left:
1/2z+10+3/4-(1/4z)=0
Domain of the equation: 2z!=0
z!=0/2
z!=0
z∈R
Domain of the equation: 4z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
1/2z-(+1/4z)+10+3/4=0
We get rid of parentheses
1/2z-1/4z+10+3/4=0
We calculate fractions
64z/128z^2+(-2z)/128z^2+6z/128z^2+10=0
We multiply all the terms by the denominator
64z+(-2z)+6z+10*128z^2=0
We add all the numbers together, and all the variables
70z+(-2z)+10*128z^2=0
Wy multiply elements
1280z^2+70z+(-2z)=0
We get rid of parentheses
1280z^2+70z-2z=0
We add all the numbers together, and all the variables
1280z^2+68z=0
a = 1280; b = 68; c = 0;
Δ = b2-4ac
Δ = 682-4·1280·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-68}{2*1280}=\frac{-136}{2560} =-17/320 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+68}{2*1280}=\frac{0}{2560} =0 $
| 9+a/4=15 | | 4(w-5)+6w=-10 | | 0.08s+s=2560 | | 120*10h=200*8h | | −1500+b+300=-1200 | | -4v+6(v+8)=28 | | 4(c-2)=-19 | | 20(3x-5)=45-30x-85 | | −3(−4−a)=5−8a/4 | | 250x+300=200x | | 10t-t-14t+17t-13t=7 | | 20(300x-500)=45-30x-85 | | k(k-2)=2(k-9) | | 30=3x+5 | | 5(2x-1)+x+17=4(x+2) | | 15w+22=-23 | | 10-5v-v=2v+2 | | 4b-6=-1+3b | | 5x+1+96=180 | | 3•-4/3-8y=4 | | 5x+1+96=90 | | 120x-1000=95x-900 | | —7x+7=-56 | | n+5=-1+3n | | 4m+6=6m-2^2 | | 4(x+1)+5(x-2)=-60 | | 3.5x=59.5 | | Y=22x+1,160 | | 15c-11c=4 | | 5+2(x+3)=x+7 | | 10-+10=10x+10 | | 4n+6=-72 |