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1/2y=10-1/3y
We move all terms to the left:
1/2y-(10-1/3y)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 3y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/2y-(-1/3y+10)=0
We get rid of parentheses
1/2y+1/3y-10=0
We calculate fractions
3y/6y^2+2y/6y^2-10=0
We multiply all the terms by the denominator
3y+2y-10*6y^2=0
We add all the numbers together, and all the variables
5y-10*6y^2=0
Wy multiply elements
-60y^2+5y=0
a = -60; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-60)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-60}=\frac{-10}{-120} =1/12 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-60}=\frac{0}{-120} =0 $
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