1/2y-8+4=-2/y-4

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Solution for 1/2y-8+4=-2/y-4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(1/2)*y-8+4 = -2/y-4 // + -2/y-4

(1/2)*y-(-2/y)-8+4+4 = 0

(1/2)*y+2*y^-1-8+4+4 = 0

1/2*y^1+2*y^-1 = 0

(1/2*y^2+2*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^2+2*y^0) = 0

y^1

(1/2)*y^2+2 = 0

(1/2)*y^2+2 = 0

DELTA = 0^2-(2*4*(1/2))

DELTA = -4

DELTA < 0

y in { } 

y belongs to the empty set

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