1/2y-(y-7/9)=1/18(Y-9)

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Solution for 1/2y-(y-7/9)=1/18(Y-9) equation: 



1/2y-(y-7/9)=1/18(-9)

We move all terms to the left:

1/2y-(y-7/9)-(1/18(-9))=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

1/2y-(+y-7/9)-(1/18(-9))=0

We get rid of parentheses

1/2y-y+7/9-(1/18(-9))=0

We calculate fractions


252y^2/324y^2-y+()/324y^2+(-(1*2y*9)/324y^2=0

We add all the numbers together, and all the variables

252y^2/324y^2-y+()/324y^2+(-(+1*2y*9)/324y^2=0

We add all the numbers together, and all the variables

252y^2/324y^2-1y+()/324y^2+(-(+1*2y*9)/324y^2=0

We multiply all the terms by the denominator


252y^2-1y*324y^2+(-(+1*2y*9)+()=0



We calculate terms in parentheses: +(-(+1*2y*9)+(), so:

-(+1*2y*9)+(

We add all the numbers together, and all the variables

-(+1*2y*9)

We get rid of parentheses

-1*2y*9

Wy multiply elements

-18y*9

Wy multiply elements

-162y

Back to the equation:

+(-162y)



Wy multiply elements

252y^2-324y^3+(-162y)=0

We get rid of parentheses

252y^2-324y^3-162y=0

We do not support eypression: y^3

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