1/2y+10=1/8y.

Solution for 1/2y+10=1/8y. equation:

1/2y+10=1/8y.

We move all terms to the left:

1/2y+10-(1/8y.)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 8y.)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/2y-(+1/8y.)+10=0

We get rid of parentheses

1/2y-1/8y.+10=0

We calculate fractions


8y/16y^2+(-2y)/16y^2+10=0

We multiply all the terms by the denominator


8y+(-2y)+10*16y^2=0

Wy multiply elements

160y^2+8y+(-2y)=0

We get rid of parentheses

160y^2+8y-2y=0

We add all the numbers together, and all the variables

160y^2+6y=0

a = 160; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·160·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*160}=\frac{-12}{320}
=-3/80
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*160}=\frac{0}{320}
=0
$