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1/2y+1/2=-2(y+1)
We move all terms to the left:
1/2y+1/2-(-2(y+1))=0
Domain of the equation: 2y!=0We calculate fractions
y!=0/2
y!=0
y∈R
-(-2(y+1))=0
We calculate terms in parentheses: -(-2(y+1)), so:We get rid of parentheses
-2(y+1)
We multiply parentheses
-2y-2
Back to the equation:
-(-2y-2)
2y+2=0
We move all terms containing y to the left, all other terms to the right
2y=-2
y=-2/2
y=-1
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