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1/2x=3x-130
We move all terms to the left:
1/2x-(3x-130)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-3x+130=0
We multiply all the terms by the denominator
-3x*2x+130*2x+1=0
Wy multiply elements
-6x^2+260x+1=0
a = -6; b = 260; c = +1;
Δ = b2-4ac
Δ = 2602-4·(-6)·1
Δ = 67624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{67624}=\sqrt{4*16906}=\sqrt{4}*\sqrt{16906}=2\sqrt{16906}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(260)-2\sqrt{16906}}{2*-6}=\frac{-260-2\sqrt{16906}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(260)+2\sqrt{16906}}{2*-6}=\frac{-260+2\sqrt{16906}}{-12} $
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