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1/2x=12+2x
We move all terms to the left:
1/2x-(12+2x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(2x+12)=0
We get rid of parentheses
1/2x-2x-12=0
We multiply all the terms by the denominator
-2x*2x-12*2x+1=0
Wy multiply elements
-4x^2-24x+1=0
a = -4; b = -24; c = +1;
Δ = b2-4ac
Δ = -242-4·(-4)·1
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{37}}{2*-4}=\frac{24-4\sqrt{37}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{37}}{2*-4}=\frac{24+4\sqrt{37}}{-8} $
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