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1/2x=(x-2)(3/4)
We move all terms to the left:
1/2x-((x-2)(3/4))=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-((x-2)(+3/4))=0
We multiply parentheses ..
-((+3x^2-2*3/4))+1/2x=0
We calculate fractions
(-((+3x^2-2*3*2x)/4)*2x)+()/4)*2x)=0
We calculate terms in parentheses: +(-((+3x^2-2*3*2x)/4)*2x), so:
-((+3x^2-2*3*2x)/4)*2x
We multiply all the terms by the denominator
-((+3x^2-2*3*2x)
We calculate terms in parentheses: -((+3x^2-2*3*2x), so:
(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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(+3x^2-2*3*2x
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