1/2x-8=4x-1

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Solution for 1/2x-8=4x-1 equation:



1/2x-8=4x-1
We move all terms to the left:
1/2x-8-(4x-1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We get rid of parentheses
1/2x-4x+1-8=0
We multiply all the terms by the denominator
-4x*2x+1*2x-8*2x+1=0
Wy multiply elements
-8x^2+2x-16x+1=0
We add all the numbers together, and all the variables
-8x^2-14x+1=0
a = -8; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·(-8)·1
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{57}}{2*-8}=\frac{14-2\sqrt{57}}{-16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{57}}{2*-8}=\frac{14+2\sqrt{57}}{-16} $

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