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1/2x-7=1/2(x-12)
We move all terms to the left:
1/2x-7-(1/2(x-12))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2(x-12))!=0We calculate fractions
x∈R
(2xx/(4x^2x+(-(1*2x)/(4x^2x-7=0
We can not solve this equation
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