If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2x-5=1/6x+3
We move all terms to the left:
1/2x-5-(1/6x+3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x+3)!=0We get rid of parentheses
x∈R
1/2x-1/6x-3-5=0
We calculate fractions
6x/12x^2+(-2x)/12x^2-3-5=0
We add all the numbers together, and all the variables
6x/12x^2+(-2x)/12x^2-8=0
We multiply all the terms by the denominator
6x+(-2x)-8*12x^2=0
Wy multiply elements
-96x^2+6x+(-2x)=0
We get rid of parentheses
-96x^2+6x-2x=0
We add all the numbers together, and all the variables
-96x^2+4x=0
a = -96; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-96)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-96}=\frac{-8}{-192} =1/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-96}=\frac{0}{-192} =0 $
| 21=-6v+3(v-2) | | -7-6-6/7=12x-31/2 | | (u-4)^2=0 | | 7x+3(×-7)=129 | | 10=j+1 | | 0=-4.9x^2-28x | | 3(x-1)=11x-8x | | 7p÷7=(-84)÷7 | | 9(y-4)=-10y+21/3 | | n÷2-1=8 | | 45+x/25-x²=0 | | 4-1x=8-3x | | 2=10–y | | 1/2x-12=1/8x | | 45+9x/25-x²=0 | | (2x+3)+(x-1)+(x+6)=180 | | ƒ(5)=4x–11 | | 4(3c-2)=12(c+2) | | -21=-6v+3(v-2 | | -14=-3n+1 | | (45+9x)/25-x²=0 | | k−427=3 | | 11+2v=-5 | | x+17=3x+9 | | -16=2w+2(w+6) | | (u-4)^2=-3u+30 | | x-0.025*x=10 | | 10–3b=7 | | (45+x)/(25-x²)=0 | | 1/5(x+5)+2(x-2)+(x-1)=28 | | 12t+24=-6 | | 20=9x+2-6 |