1/2x-5+2/3x=7/6x+4

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Solution for 1/2x-5+2/3x=7/6x+4 equation: 


x in (-oo:+oo)

(1/2)*x+(2/3)*x-5 = (7/6)*x+4 // - (7/6)*x+4

(1/2)*x+(2/3)*x-((7/6)*x)-5-4 = 0

(1/2)*x+(2/3)*x+(-7/6)*x-5-4 = 0

-9 = 0

x belongs to the empty set

x belongs to the empty set

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