1/2x-4=2x+5*

Solution for 1/2x-4=2x+5* equation:

1/2x-4=2x+5*

We move all terms to the left:

1/2x-4-(2x+5*)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x-(+2x)-4=0

We get rid of parentheses

1/2x-2x-4=0

We multiply all the terms by the denominator


-2x*2x-4*2x+1=0

Wy multiply elements

-4x^2-8x+1=0

a = -4; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·(-4)·1
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{5}}{2*-4}=\frac{8-4\sqrt{5}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{5}}{2*-4}=\frac{8+4\sqrt{5}}{-8}
$