1/2x-4=1/4x+12

Solution for 1/2x-4=1/4x+12 equation:

1/2x-4=1/4x+12

We move all terms to the left:

1/2x-4-(1/4x+12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+12)!=0

x∈R


We get rid of parentheses

1/2x-1/4x-12-4=0

We calculate fractions


4x/8x^2+(-2x)/8x^2-12-4=0

We add all the numbers together, and all the variables

4x/8x^2+(-2x)/8x^2-16=0

We multiply all the terms by the denominator


4x+(-2x)-16*8x^2=0

Wy multiply elements

-128x^2+4x+(-2x)=0

We get rid of parentheses

-128x^2+4x-2x=0

We add all the numbers together, and all the variables

-128x^2+2x=0

a = -128; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-128)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-128}=\frac{-4}{-256}
=1/64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-128}=\frac{0}{-256}
=0
$