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1/2x-3=5.x
We move all terms to the left:
1/2x-3-(5.x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(+5.x)-3=0
We get rid of parentheses
1/2x-5.x-3=0
We multiply all the terms by the denominator
-(5.x)*2x-3*2x+1=0
We add all the numbers together, and all the variables
-(+5.x)*2x-3*2x+1=0
We multiply parentheses
-10x^2-3*2x+1=0
Wy multiply elements
-10x^2-6x+1=0
a = -10; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-10)·1
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{19}}{2*-10}=\frac{6-2\sqrt{19}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{19}}{2*-10}=\frac{6+2\sqrt{19}}{-20} $
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