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1/2x-3/4x=2-6
We move all terms to the left:
1/2x-3/4x-(2-6)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
1/2x-3/4x-(-4)=0
We add all the numbers together, and all the variables
1/2x-3/4x+4=0
We calculate fractions
4x/8x^2+(-6x)/8x^2+4=0
We multiply all the terms by the denominator
4x+(-6x)+4*8x^2=0
Wy multiply elements
32x^2+4x+(-6x)=0
We get rid of parentheses
32x^2+4x-6x=0
We add all the numbers together, and all the variables
32x^2-2x=0
a = 32; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·32·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*32}=\frac{0}{64} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*32}=\frac{4}{64} =1/16 $
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