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1/2x-2=6x-4
We move all terms to the left:
1/2x-2-(6x-4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-6x+4-2=0
We multiply all the terms by the denominator
-6x*2x+4*2x-2*2x+1=0
Wy multiply elements
-12x^2+8x-4x+1=0
We add all the numbers together, and all the variables
-12x^2+4x+1=0
a = -12; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-12)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*-12}=\frac{-12}{-24} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*-12}=\frac{4}{-24} =-1/6 $
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