1/2x-2=3x-10

Solution for 1/2x-2=3x-10 equation:

1/2x-2=3x-10

We move all terms to the left:

1/2x-2-(3x-10)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-3x+10-2=0

We multiply all the terms by the denominator


-3x*2x+10*2x-2*2x+1=0

Wy multiply elements

-6x^2+20x-4x+1=0

We add all the numbers together, and all the variables

-6x^2+16x+1=0

a = -6; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·(-6)·1
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{70}}{2*-6}=\frac{-16-2\sqrt{70}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{70}}{2*-6}=\frac{-16+2\sqrt{70}}{-12}
$