1/2x-16=2x+4

Solution for 1/2x-16=2x+4 equation:

1/2x-16=2x+4

We move all terms to the left:

1/2x-16-(2x+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-2x-4-16=0

We multiply all the terms by the denominator


-2x*2x-4*2x-16*2x+1=0

Wy multiply elements

-4x^2-8x-32x+1=0

We add all the numbers together, and all the variables

-4x^2-40x+1=0

a = -4; b = -40; c = +1;
Δ = b2-4ac
Δ = -402-4·(-4)·1
Δ = 1616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1616}=\sqrt{16*101}=\sqrt{16}*\sqrt{101}=4\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-4\sqrt{101}}{2*-4}=\frac{40-4\sqrt{101}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+4\sqrt{101}}{2*-4}=\frac{40+4\sqrt{101}}{-8}
$