1/2x-12=0.5x-12

Solution for 1/2x-12=0.5x-12 equation:

1/2x-12=0.5x-12

We move all terms to the left:

1/2x-12-(0.5x-12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-0.5x+12-12=0

We multiply all the terms by the denominator


-(0.5x)*2x+12*2x-12*2x+1=0

We add all the numbers together, and all the variables

-(+0.5x)*2x+12*2x-12*2x+1=0

We multiply parentheses

-0x^2+12*2x-12*2x+1=0

Wy multiply elements

-0x^2+24x-24x+1=0

We add all the numbers together, and all the variables

-1x^2+1=0

a = -1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1)·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-1}=\frac{-2}{-2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-1}=\frac{2}{-2}
=-1
$