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1/2x-1/6x=-5
We move all terms to the left:
1/2x-1/6x-(-5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
1/2x-1/6x+5=0
We calculate fractions
6x/12x^2+(-2x)/12x^2+5=0
We multiply all the terms by the denominator
6x+(-2x)+5*12x^2=0
Wy multiply elements
60x^2+6x+(-2x)=0
We get rid of parentheses
60x^2+6x-2x=0
We add all the numbers together, and all the variables
60x^2+4x=0
a = 60; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·60·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*60}=\frac{-8}{120} =-1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*60}=\frac{0}{120} =0 $
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