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1/2x+8=6x+19
We move all terms to the left:
1/2x+8-(6x+19)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-6x-19+8=0
We multiply all the terms by the denominator
-6x*2x-19*2x+8*2x+1=0
Wy multiply elements
-12x^2-38x+16x+1=0
We add all the numbers together, and all the variables
-12x^2-22x+1=0
a = -12; b = -22; c = +1;
Δ = b2-4ac
Δ = -222-4·(-12)·1
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{133}}{2*-12}=\frac{22-2\sqrt{133}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{133}}{2*-12}=\frac{22+2\sqrt{133}}{-24} $
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