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1/2x+6=3/2(x+6
We move all terms to the left:
1/2x+6-(3/2(x+6)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2(x+6)+6!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
2(x+6)!=-6
x∈R
(2x(x+6)/(4x^2(x+6)+(-(3*2x)/(4x^2(x+6)=0
We calculate terms in parentheses: +(2x(x+6)/(4x^2(x+6)+(-(3*2x)/(4x^2(x+6), so:
2x(x+6)/(4x^2(x+6)+(-(3*2x)/(4x^2(x+6
We can not solve this equation
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