1/2x+6=2x-4

Solution for 1/2x+6=2x-4 equation:

1/2x+6=2x-4

We move all terms to the left:

1/2x+6-(2x-4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-2x+4+6=0

We multiply all the terms by the denominator


-2x*2x+4*2x+6*2x+1=0

Wy multiply elements

-4x^2+8x+12x+1=0

We add all the numbers together, and all the variables

-4x^2+20x+1=0

a = -4; b = 20; c = +1;
Δ = b2-4ac
Δ = 202-4·(-4)·1
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{26}}{2*-4}=\frac{-20-4\sqrt{26}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{26}}{2*-4}=\frac{-20+4\sqrt{26}}{-8}
$