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1/2x+6-2x=-5-x
We move all terms to the left:
1/2x+6-2x-(-5-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-2x-(-1x-5)+6=0
We add all the numbers together, and all the variables
-2x+1/2x-(-1x-5)+6=0
We get rid of parentheses
-2x+1/2x+1x+5+6=0
We multiply all the terms by the denominator
-2x*2x+1x*2x+5*2x+6*2x+1=0
Wy multiply elements
-4x^2+2x^2+10x+12x+1=0
We add all the numbers together, and all the variables
-2x^2+22x+1=0
a = -2; b = 22; c = +1;
Δ = b2-4ac
Δ = 222-4·(-2)·1
Δ = 492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{492}=\sqrt{4*123}=\sqrt{4}*\sqrt{123}=2\sqrt{123}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{123}}{2*-2}=\frac{-22-2\sqrt{123}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{123}}{2*-2}=\frac{-22+2\sqrt{123}}{-4} $
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