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1/2x+5=2/4x+1
We move all terms to the left:
1/2x+5-(2/4x+1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x+1)!=0We get rid of parentheses
x∈R
1/2x-2/4x-1+5=0
We calculate fractions
4x/8x^2+(-4x)/8x^2-1+5=0
We add all the numbers together, and all the variables
4x/8x^2+(-4x)/8x^2+4=0
We multiply all the terms by the denominator
4x+(-4x)+4*8x^2=0
Wy multiply elements
32x^2+4x+(-4x)=0
We get rid of parentheses
32x^2+4x-4x=0
We add all the numbers together, and all the variables
32x^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{64}=0$
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