1/2x+5=-4x-4

Solution for 1/2x+5=-4x-4 equation:

1/2x+5=-4x-4

We move all terms to the left:

1/2x+5-(-4x-4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x+4x+4+5=0

We multiply all the terms by the denominator


4x*2x+4*2x+5*2x+1=0

Wy multiply elements

8x^2+8x+10x+1=0

We add all the numbers together, and all the variables

8x^2+18x+1=0

a = 8; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·8·1
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{73}}{2*8}=\frac{-18-2\sqrt{73}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{73}}{2*8}=\frac{-18+2\sqrt{73}}{16}
$