1/2x+5=-2+2x

Solution for 1/2x+5=-2+2x equation:

1/2x+5=-2+2x

We move all terms to the left:

1/2x+5-(-2+2x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x-(2x-2)+5=0

We get rid of parentheses

1/2x-2x+2+5=0

We multiply all the terms by the denominator


-2x*2x+2*2x+5*2x+1=0

Wy multiply elements

-4x^2+4x+10x+1=0

We add all the numbers together, and all the variables

-4x^2+14x+1=0

a = -4; b = 14; c = +1;
Δ = b2-4ac
Δ = 142-4·(-4)·1
Δ = 212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{212}=\sqrt{4*53}=\sqrt{4}*\sqrt{53}=2\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{53}}{2*-4}=\frac{-14-2\sqrt{53}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{53}}{2*-4}=\frac{-14+2\sqrt{53}}{-8}
$