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1/2x+5/4=-2/3x
We move all terms to the left:
1/2x+5/4-(-2/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
1/2x+2/3x+5/4=0
We calculate fractions
90x^2/96x^2+48x/96x^2+64x/96x^2=0
We multiply all the terms by the denominator
90x^2+48x+64x=0
We add all the numbers together, and all the variables
90x^2+112x=0
a = 90; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·90·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*90}=\frac{-224}{180} =-1+11/45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*90}=\frac{0}{180} =0 $
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