1/2x+5(1/4x-14)=-63

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Solution for 1/2x+5(1/4x-14)=-63 equation:



1/2x+5(1/4x-14)=-63
We move all terms to the left:
1/2x+5(1/4x-14)-(-63)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x-14)!=0
x∈R
We add all the numbers together, and all the variables
1/2x+5(1/4x-14)+63=0
We multiply parentheses
1/2x+5x-70+63=0
We multiply all the terms by the denominator
5x*2x-70*2x+63*2x+1=0
Wy multiply elements
10x^2-140x+126x+1=0
We add all the numbers together, and all the variables
10x^2-14x+1=0
a = 10; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·10·1
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{39}}{2*10}=\frac{14-2\sqrt{39}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{39}}{2*10}=\frac{14+2\sqrt{39}}{20} $

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